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Python loop for finding the index of an array
I am trying to search for an element in an array using a loop and want to return the index of the element found. My approach was to convert my array into a list and then convert that back into an array. The first part seems to work fine but the back conversion to an array isn't working.
I tried running the program as follows:
array = [1, 2, 3, 4]
def search_and_return_index(array):
list_array = list(array)
array_object = array_list[:]
for x in list_array:
if x == 4:
print(array_object.index(x))
break
return array_object.index(x)
The output i am getting when i run this is as follows:
TypeError: '>=' not supported between instances of 'list' and 'list'
The output that i want is the index of the first element that is greater than 4.
Any help would be appreciated.
Thanks
A:
I would advise you to use an algorithm that doesn't have an index i returned by default as it's unclear in which order you want to compare against the value.
def search_and_return_index(array):
array_object = array[:]
for x in array_object:
if x > 4:
return x
This will return the first value that is greater than 4.
If you want to return all elements that are greater than 4, you can easily loop over the result of the previous method.
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